Are you done know linear velocity of numerical control lathe Vc?

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(the article achieves formerly by Mr. Zou Jun) 3 relevant statements: G97: Main shaft rotate speed controls (R/min) G96: Fast speed controls the route (M/min)G50: Main shaft is highest the set of rotate speed (M/min) you input G97 S1000 in the machine tool, tell a machine tool main shaft to minutely meeting rotates namely 1000 turn. G97 instruction controls main shaft rotate speed. (if your program is medium,do not write G97, direct S1000, main shaft still is meeting 1000r/min, because of G97 of machine tool acquiesce, in process designing moment this instruction can omit. G96: Linear velocity controls you to input G96 S200 in the machine tool, so linear velocity of machine tool main shaft is 200, what recall with deep emotion is this? Linear velocity, linear velocity actually namely rate rate = is apart from / if time has a spare parts diameter it is D133.

You need O with S300 (turn / minute) come the circle outside the car, so this spare parts (D133) minutely the distance that how long rotates? Be apart from =3.

14*D *S (D is a diameter, is S rotate speed) so how is linear velocity to calculate? Also be speed = distance / quantum of time is: Rice / minute time is = of a minute of linear velocity (3.

14*133.

0*300) / 1? ? Right? Incorrect, because the unit regulation of linear velocity is: Rice / minute, unit of spare parts diameter is millimeter (Mm) , so need conversion becomes rice (M) divide even namely with 1000 so linear velocity is as follows: Linear velocity = (3.

14*133.

0*300) / 1000 so your car end panel, reach spare parts center from diametical D133 car O position, if I dictate according to acquiesce G97 S200, reach diametical D10 point when the car, so how much is right now linear velocity? The answer is: 6.

= of 28 M/min linear velocity (3.

14*D*S) / 1000 jump over as the diameter small, linear velocity is smaller. We are so good to achieve when car external diameter changes bright and clean degree, use linear velocity as far as possible please.

What affect a part of course is bright and clean degree, the element is very much, for instance cutting tool is a very main reason, cutting deepness, feed is waited a moment, did not say more in this. Using linear velocity time, we need to cooperate G50 to dictate (main shaft is highest the set of rotate speed) if the circle outside the car, what you use is linear velocity, be like G96S200 diameter D1 =ØD2 = of 50 Mm diameterØ80 Mm so how much is its rotate speed respectively? The answer is respectively: Does 1274 R/min, 318m/min see clue is done not have? ? S=Vc*1000/(3, 14*D) Vc: ? Dong Yu? , diameter of D spare parts is jumped over as straight D diameter small, rotate speed will be higher and higher. So: Using linear velocity time, we need to cooperate G50 to dictate (main shaft is highest the set of rotate speed) the diameter is smaller, when using linear velocity, rotate speed is met taller and taller, this cooperates G50 to dictate with respect to need for instance: T1G96S200G50S2000 (rotate speed of machine tool main shaft cannot exceed 2000r/min) G0Z2.

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